MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        

A cat of mass 1 kg moves up  on an massless string which goes along a friction less pulley so as to just lift a block of mass 2 kg.After sometime the cat stops moving with respect to the string .The magnitude of change in cats acceleration is?

8 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
							

Dear Debadutta,

initial upward acceleration of cat=g

final acceleration=(2-1)g/(2+1)=g/3 upward

change in cat's acceleration=g-(g/3)=2g/3

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best Debadutta !!!

 


Regards,

Askiitians Experts

CHETAN MANDAYAM NAYAKAR

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details