when a spring is divided into two parts in the ratio 1:2 does it mean if we take one to be spring constant to be k1 the other becomes 2k1?
shreya naik , 14 Years ago
Grade 11
5 Answers
SAGAR SINGH - IIT DELHI
Last Activity: 14 Years ago
Dear student, Yes very correct k1 and 2k1 will be the spring constants... Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Durgesh Prasher
Last Activity: 14 Years ago
no spring constant depends on nature of materials
vikas askiitian expert
Last Activity: 14 Years ago
k(spring constant) inversly proportional to l(length) ...
k1/k = L/L1
length of two parts are L/3 , 2L/3
comparing spring constant of each part with original we get
k1 = 3k (spring constant of smaller part)
k2 = 3k/2 (spring constant of larger part)
vishvendra
Last Activity: 8 Years ago
Sir u r wrong @sagar Because if a spring is cut in m:n .Then the resultant springs having stiffness (m+n)/n and (m+n)/m respectively .VSYMADE EASY
Mukul
Last Activity: 7 Years ago
Spring constant is inversely proportional to length but from your formula it is directly proportional so please render changes in your formula The correct formula should be If spring is cut in ratio m:n then(m+n)/m and (m+n)/n
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