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when a spring is divided into two parts in the ratio 1:2 does it mean if we take one to be spring constant to be k1 the other becomes 2k1?

shreya naik , 14 Years ago
Grade 11
anser 5 Answers
SAGAR SINGH - IIT DELHI

Last Activity: 14 Years ago

Dear student,
Yes very correct k1 and 2k1 will be the spring constants...
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Sagar Singh
B.Tech, IIT Delhi

Durgesh Prasher

Last Activity: 14 Years ago

no spring constant depends on nature of materials

vikas askiitian expert

Last Activity: 14 Years ago

k(spring constant) inversly proportional to l(length) ...

k1/k = L/L1 

length of two parts are L/3 , 2L/3

comparing spring constant of each part with original we get

k1  = 3k (spring constant of smaller part)

k2 = 3k/2 (spring constant of larger part)

vishvendra

Last Activity: 8 Years ago

Sir u r wrong @sagar Because if a spring is cut in m:n .Then the resultant springs having stiffness (m+n)/n and (m+n)/m respectively .VSYMADE EASY

Mukul

Last Activity: 7 Years ago

Spring constant is inversely proportional to length but from your formula it is directly proportional so please render changes in your formula The correct formula should be If spring is cut in ratio m:n then(m+n)/m and (m+n)/n

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