vikas askiitian expert
Last Activity: 14 Years ago
after releasing the system , heavy block moves in the influence of gravity & gains some speed ...there is no tension in rod...
after covering H distance , rod & particle are horizontally in same level with ring ....now tension is present as the hook gets into the ring...
now block moves in circle .... let at this point potential is 0 ...
now applying energy conservation bw the topmost point of circle & initial point ...
mv2/2 + 0 = mv12/2 + mgL (v = initial speed , v1 final speed)
mv2/2 = mgH , so
mgH - mgL = mv12/2 ....................1
at final state ,let T is tension then
T+mg = mv12 /L (centripital force)
if tension is 0 then also block can complete the circle so
mv12 = mgL ................2
using 1 & 2
mgH = mg(3L/2)
H = 3L/2
approve my ans if u like it