Guest

FROM A CIRCULAR DISC OF RADIUS R AND MASS 9M, A SMALL DISC OF RADIUS R/3 IS REMOVED FROM THE DISC. THE M.O.INERTIA OF THE REMAINING DISC ABOUT AN AXIS PERPENDICULAR TO THE PLANE OF THE DISC AND PASSING THRO' IT'S CENTER IS:

FROM A CIRCULAR DISC OF RADIUS R AND MASS 9M, A SMALL DISC OF RADIUS R/3 IS REMOVED FROM THE DISC. THE M.O.INERTIA OF THE REMAINING DISC ABOUT AN AXIS PERPENDICULAR TO THE PLANE OF THE DISC AND PASSING THRO' IT'S CENTER IS: 

Grade:11

3 Answers

Ritvik Gautam
85 Points
11 years ago

it will be the same...

Shahid Akbar
33 Points
8 years ago
Its will be 4MR*2 BY using parallel axis theorem
Jay Gohil
28 Points
5 years ago
Let I1 be the moment of Inertia of bigger circle and I2 of smaller circleI=I1- I2=9mr^2/2-mr^2/18=80mr^2/18=40mr^2/9

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free