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the moment of inertia of a uniform rod of length 2l and mass m about an axis xx passing thro' it's center and inclined at an angle alpha is
we know that the moment of inertia of a uniform rod is
ml2 sin2 Θ/12
so here length is 2l and Θ=α
substituting, we get..
4ml2 sin2 α/12
==> ml2sin2 α/3
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