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A rail road is moving with a constant acceleration of 1 m/s2 a block of 5 kg is put on a horizontal rough road floor in the car. at time t = 0, velocity of the car is 5m/s . Considering friction is sufficient and block is not slipping on the floor , the work done on the block by friction force during t= 0 to t = 2 sec will be (cofficient of friction is )???
seudo force acts on the block placed on car...
Fseudo = ma (a is accleration of car)
=5*1=5N
now since the block is not slipping so friction is sufficient to balance the the suedo force ...
ffriction = Fseudo = 5N
during t=0 to t=2 sec , displacement of car is
S = ut + .5at2
S = 12 m (a=1m/s2 , u =5m/s , t=2 )
workdone by friction = f.X = 5*12 = 60N
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