Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A tank contains water on top of mercury.A cube of iron,60mm along each edge,is sitting upright in equilibrium in the liquids.Find how much of it is in each liquid.The densities of iron and mercury are 7.7g/cm3 and 13.6g/cm3 respectively
Dear Sohan
Suppose x1 length is in water and x2 in mercury
and x1+x2=h=60mm...............(1)
here equilibrium equation will be
Weight = total buoyant force for each medium, W=B=Bw + Bhg...........(2)
weight=W= density of cubex volumexg= dcx(Axh)xg, where A is h2
Bw=dw*(A*x1)*g
Bhg=dhg*(A*x2)*g
use equation 2
after cancelling terms on rhs and lhs you will get
dc*h=dw*x1+dhg*x2
put values of density
7.7h=x1+13.6x2..............(3)
solve for x1 and x2 using 1 and 3
x2=6.7h/12.6= 6.7*60/12.6 = 31.9 mm in mercury
in water=60-31.9=28.1 mm
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !