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Q.12 A diwali cracker known as sudarashan chakra works on the principle of thrust. Consider such a toy the centre of which is hinged.The initial mass of the toy is M() and radius is R. The toy is in the shape of a spiral the turns of which are very close (it can be assumed as a disc ).The gases are ejected tangentially from the end of the toy with a constant velocity u relative to the toy. Find the angular velocity ofthe toy when mass remains half.
well.. in this we just need to conserve the angular momentum...
Initially,
Angular momentum = IW
==> MR2U/2R ....................... (v=rw)
==> MRU/2
Finally, assuming the radius to be halfed as mass is halfed..
==> MR2 W/8
Initial and final angular momentum is conserved
==> MRU/2=MR2 W/8
==>W=8U/R2
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