Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

265_23993_Photo0148.jpg

Grade:12

1 Answers

vikas askiitian expert
509 Points
10 years ago

let its velocity  was v when it was in circular motion...after the string breaks , stone will move parabolically...

H = 2.7 (above the ground)

Ux= v       (velocity in circular path)

ay = -g

for horizontal motion threre is no accleration so ax =0

for verticle motion ,

S = gt2/2

2.7 = gt2/2

t = 0.74sec

now for horizontal motion

speed = distance/time

 Ux = 10/(0.74)                                   (distance 10m (given))

Ux = 13.51m/s

with this velocity particle was circulating .....

ac(centripital accleration) = v2/r = (13.51)2/1.5 = 122 m/s2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free