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let its velocity was v when it was in circular motion...after the string breaks , stone will move parabolically... H = 2.7 (above the ground) Ux= v (velocity in circular path) ay = -g for horizontal motion threre is no accleration so ax =0 for verticle motion , S = gt2/2 2.7 = gt2/2 t = 0.74sec now for horizontal motion speed = distance/time Ux = 10/(0.74) (distance 10m (given)) Ux = 13.51m/s with this velocity particle was circulating ..... ac(centripital accleration) = v2/r = (13.51)2/1.5 = 122 m/s2
let its velocity was v when it was in circular motion...after the string breaks , stone will move parabolically...
H = 2.7 (above the ground)
Ux= v (velocity in circular path)
ay = -g
for horizontal motion threre is no accleration so ax =0
for verticle motion ,
S = gt2/2
2.7 = gt2/2
t = 0.74sec
now for horizontal motion
speed = distance/time
Ux = 10/(0.74) (distance 10m (given))
Ux = 13.51m/s
with this velocity particle was circulating .....
ac(centripital accleration) = v2/r = (13.51)2/1.5 = 122 m/s2
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