Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1975_23993_Photo0147.jpg

Grade:12

1 Answers

vikas askiitian expert
509 Points
10 years ago

let particle are at A,B,C...

force on A due to B is F & force on A due to C is also F...

F = Gm2/a2

net force  = (F2+F2+2F2cos@)1/2                                 (by vector method)

angle bw them is @ = 60

so net force = Fn = 31/2F       ...........1

due to this force ,each particle circulates aroung their center of mass & center of mass lies at the center of equilateral triangle ......

Fc = Fn = 31/2Gm2/a2   

mv2/r = 31/2Gm2/a2

  v = {31/2 Gm/a2r}1/2 

 now r = a/31/2        

 now v becomes

 v = {3Gm/a3}1/2                                             ans1

time period = 2pir/v

                =2pi(a/31/2){3Gm/a3)1/2

               = 2pi(gm/a)1/2                             ans2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free