Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A flywheel whose moment of inertia about its axis of rotation is 16kg/m2 is rotating freely in its own plane about a smooth axis through its center. Its angular velocit is 9 rad/s when a torque is applied to bring it to rest in t0 second. Find 0t if
a)the torque is constant(=4Nm)
b)the magnitude of the torque after t secnds is given by kt.
torque = I(alfa)
case 1) I(alfa) = 4
alfa = 4/I =4/16 = 0.25rad/s2
for constant torque we can apply , w = wi + (alfa)t
since torque is retarding so w = wi-(alfa)t
final body stops so w = 0 , wi=9rad/sec (given)
t = alfa/wi = 0.25/9 = 0.0277sec
case2) torque = I(alfa)
alfa = kt/I = -kt/16 (when k > 0 )
alfa = dw/dt
dw/dt = -kt/16
w = -kt2/32 + c (c is constant of integration)
at t=0 , w = 9 , putting this in above expression
c = 9
w = -kt2/32+ 9
when body comes to rest then w = 0
t = (32*9/k)1/2 = 12root(2/k)
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !