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A RESEARCH SATELLITE OF MASS 200 KG CIRCLES IN AN ORBIT of averge radius of 3R/2 WHERE R is the radius of the earth. Aasuuming that the gravitational pull on the mass of 1 kg on the earth's surface is 10N, the pull on the satelite is --------------

```
9 years ago

```							accleration due to gravity at surface(gs)= GM/R2
accleration due to gravity at a height (gh) = GM/(R+H)2
force on a particle of 1kg at surface  = mGM/R2 =GM/R2 = 10N     ......1           (given)
force on satellite of mass 200kg at a height H  = mGM/(R+H)2
F = 200GM/(R+H)2  .............2
dividing 2 by 1
F/10 = 200/(1+H/R)2
=2000(4/25)                      (H=3R/2)
=320N

```
9 years ago
```							let us take mass of earth as Me then 10=GMe.1/R^2   -----1now mass of satellite =200 kg let us take force on it as F then,F=GMe.200/(3R/2)^2-------2dividing 2by 1F/10=200/9/4F/10=800/9 hence f=8000/9=888.8=889N
```
5 years ago
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