vikas askiitian expert
Last Activity: 14 Years ago
accleration due to gravity at surface(gs)= GM/R2
accleration due to gravity at a height (gh) = GM/(R+H)2
force on a particle of 1kg at surface = mGM/R2 =GM/R2 = 10N ......1 (given)
force on satellite of mass 200kg at a height H = mGM/(R+H)2
F = 200GM/(R+H)2 .............2
dividing 2 by 1
F/10 = 200/(1+H/R)2
=2000(4/25) (H=3R/2)
=320N