Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A rod of length L is hinged from one end.It is brougt to horizontal position and then released. the angular velocity of the rod when it is in vertical positon
wrt initial position of rod , when roD is verticle then center of mass of rod has fallen a height of L/2.....
now , applying conservation of energy
change in (kE) = difference in potential energy
IW2/2 = mgdh
(mL2/3)(W2/2) = mg(L/2)
W =(3g/L)1/2
Irod = mL2/3 , dh = L/2
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !