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a particle moving in a circle with a constant speed covers an angle of 90degrees .the change in its velocity is ??????in terms of v

419 Points
10 years ago

In 90 degree it will cover one fourth of the perimeter

suppose speed is v then time taken t=2∏r/4v=∏r/2v

velocity=displacement/time

displacement=√r2+r2 =r√2

velocity=r√2/t = 2√2 v/∏

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debdeep bhandari
14 Points
10 years ago

initial velocity is vi and final velocity is vj,,,,,so the net velocity is vj-vi,,,,whose magnitude is(v2+v2).5