a particle moving in a circle with a constant speed covers an angle of 90degrees .the change in its velocity is ??????in terms of v

Dear Aditya

In 90 degree it will cover one fourth of the perimeter

suppose speed is v then time taken t=2∏r/4v=∏r/2v

velocity=displacement/time

displacement=√r²+r² =r√2

velocity=r√2/t = 2√2 v/∏

All the best.                                                           

AKASH GOYAL

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initial velocity is vi and final velocity is vj,,,,,so the net velocity is vj-vi,,,,whose magnitude is(v²+v²)^.5