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a smooth rod of 4kg rests on two supports A and B. From a point c at its centre 9kg is suspended by a string of length 1 m. when θ is 30 deg it is released from rest. find maximum displacement of rod. ans given is 0.2 m please explain
Dear student, Elasticity and area of cross section are required to find the deflection only due to weight. let x be the initial deflection, force due to pendulum is maximum when it is at mean position => velocity at mean position is = [2g*l(1-cos(theta)]^1/2 force at mean position = mv^2/l => 9*g/1 = 90N so maximum deflection will be 2x.
Dear student,
Elasticity and area of cross section are required to find the deflection only due to weight.
let x be the initial deflection,
force due to pendulum is maximum when it is at mean position
=> velocity at mean position is = [2g*l(1-cos(theta)]^1/2
force at mean position = mv^2/l
=> 9*g/1 = 90N
so maximum deflection will be 2x.
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