 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        A body of mass m moving with velocity u collides with another ball of mass m2 at rest. the ratio m1/m2 for maximum energy transfer is:
ans:1

in the worked out solution:
ΔK.E/K.E has been worked out as 4n/(1+n)^2
where n=m1/m2 and ΔK.E is decrease in K.E.
then, d/dn(4n/(1+n)^2) = 0
so n=1

can you please explain the differentiation part?
Is there any other method?```
9 years ago

```							change of KE /KE = 4n/(n+1)2 or
change in KE depend upon 4n/(n+1)2        for a particular value of initial KE...
this means dKE is a function of n                 (where n is variable...)
now we have to maximise this change for this we can use concept of maxima & minima ...
dKE = f(n) = 4n/(n+1)2
differentiating this eq wrt n
d/dn [f(n)] = d/dn [4n/(n+1)2 ]
=4[-n2 + 1]/(n+1)4                           (using quotient rule)
now putting the above expression equal to 0
-n2+1 = 0
n=+1 or -1
now we have two values for n ,on substituting these values we will see that function
is maximum at n=1 & minimum at n=-1 so n=1 is the value for which kinetic energy transferred is maximum...
```
9 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions