vikas askiitian expert
Last Activity: 14 Years ago
change of KE /KE = 4n/(n+1)2 or
change in KE depend upon 4n/(n+1)2 for a particular value of initial KE...
this means dKE is a function of n (where n is variable...)
now we have to maximise this change for this we can use concept of maxima & minima ...
dKE = f(n) = 4n/(n+1)2
differentiating this eq wrt n
d/dn [f(n)] = d/dn [4n/(n+1)2 ]
=4[-n2 + 1]/(n+1)4 (using quotient rule)
now putting the above expression equal to 0
-n2+1 = 0
n=+1 or -1
now we have two values for n ,on substituting these values we will see that function
is maximum at n=1 & minimum at n=-1 so n=1 is the value for which kinetic energy transferred is maximum...