A machine gun fires 25g bullates at the rate of 600 per minute with a speed of 400 m/s . Calculate the force required to keep the gun in position.
Gun fires 600 bullets in 1 minute so,
no.of bullets fired in 1 second=10
now time taken by 1 bullet to get fired=1/10sec=0.1sec
initial velocity u=0m/s
final velocity v=400m/s
v=u+at
400=0.1a
a=4000m/s2
now,force exerted by the bullet on the gun=force required to keep the gun in position
so,force exerted by 1 bullet f=ma=25*10-3*4000=100newtons
force exerted by 600 bullets=100*600=60000N
The mass of one bullet is 25g=25/1000 kg
velocity of each bullet = 400m/s
therefore the momentum of each bullet=25/1000*400
momentum of 600 bullets(P) =25/1000*400*600
initial momentum of the bullets is zero and the rate of change of momentum=force applied by the bullets on the gun
to balance this force an equal and opposite force is to be applied to keep the gun in position
therefore force=P/60
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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