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A block of mass m slides down an inclined plane of inclination ? with uniform speed. The coefficient of friction between the block and the plane is µ . Find the contact force between the block and the plane.
The normal reaction for the block on the plane is mgcos? . The contact force between them is the friction(f)=µmgcos? µmgcos? .
The normal reaction for the block on the plane is mgcos? .
The contact force between them is the friction(f)=µmgcos?
µmgcos? .
If the speed is to be constant then there shouldn't be no accelaration..The condition is tan(angle of inclination of the inclined plane)=coefficient of friction.
since the block is moving with constant velocity that means net force acting on the body is 0.. friction force(f) = mgsin@ ...............1 f = u(normal reaction) f =uN mgsin@ = uN N = mgsin@/u (contact force)
since the block is moving with constant velocity that means net force acting on the body is 0..
friction force(f) = mgsin@ ...............1
f = u(normal reaction)
f =uN
mgsin@ = uN
N = mgsin@/u (contact force)
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