A block of mass m slides down an inclined plane of inclination ? with uniform speed. The coefficient of friction between the block and the plane is µ . Find the contact force between the block and the plane.

Question

Shankararama Sharma · Answer

The normal reaction for the block on the plane is mgcos ? . The contact force between them is the friction(f)= &micro;mgcos? &micro;mgcos? .

Aniket Patra · Answer

If the speed is to be constant then there shouldn't be no accelaration..The condition is tan(angle of inclination of the inclined plane)=coefficient of friction.

vikas askiitian expert · Answer

since the block is moving with constant velocity that means net force acting on the body is 0..

friction force(f) = mgsin@ ...............1

f = u(normal reaction)

f =uN

mgsin@ = uN

N = mgsin@/u (contact force)

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A block of mass m slides down an inclined plane of inclination ? with uniform speed. The coefficient of friction between the block and the plane is µ . Find the contact force between the block and the plane.

A block of mass m slides down an inclined plane of inclination ? with uniform speed. The coefficient of friction between the block and the plane is µ . Find the contact force between the block and the plane.

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