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Grade 10Mechanics

A car starts from rest. It has to cover a distance of 500 m. the coefficient of friction between the road and the tyre is 0.5. The minimum time in which the car can cover this distance is (g=10m/ s2 ).

Profile image of Kaushik Ram
15 Years agoGrade 10
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1 Answer

Profile image of Aman Bansal
15 Years ago

dear kaushik ram,

the car moves due to the frictional force provided due to the motion of tyres in opposite direction,

the frictional force = μmg

therefore acceleration provided due to friction is 0.5*10

and using second law of motion,

s=ut + 1/2*a*t2

t=2001/2sec.

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AMAN BANSAL

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