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Grade: 10
        A car starts from rest. It has to cover a distance of 500 m. the coefficient of friction between the road and

the tyre is 0.5. The minimum time in which the car can cover this distance is (g=10m/ s2 ).
7 years ago

Answers : (1)

Aman Bansal
592 Points
							

dear kaushik ram,

the car moves due to the frictional force provided due to the motion of tyres in opposite direction,

the frictional force = μmg

therefore acceleration provided due to friction is 0.5*10

and using second law of motion,

s=ut + 1/2*a*t2

t=2001/2sec.

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AMAN BANSAL

7 years ago
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