AJIT AskiitiansExpert-IITD
Last Activity: 13 Years ago
Dear kaushik ,
(a) AS we increase the angle the force of gravity along the incline i.e mgsinθ increases and the normal component to the plane mgcosθ decreases . SO , the maximum angl is reached when the downward force equals the maximum friction force.
so , mgsinθ = µmgcosθ
so maximum angle is θ = tan-1 (µ) = tan-1 (.3) = 16.7 deg
b) when the angle is lesser than the maximum value the force of friction equals the downward push due to gravity , mgsinθ/2
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