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The coefficient of static friction between a block of mass m and the incline is 0.3. of the incline plane with the horizontal such that the block does not slip on the plane? θ / 2 with the horizontal, find the frictional force on the block. (a) What can be the maximum angle θ (b) If the incline plane makes an angle
Dear kaushik , (a) AS we increase the angle the force of gravity along the incline i.e mgsinθ increases and the normal component to the plane mgcosθ decreases . SO , the maximum angl is reached when the downward force equals the maximum friction force. so , mgsinθ = µmgcosθ so maximum angle is θ = tan-1 (µ) = tan-1 (.3) = 16.7 deg b) when the angle is lesser than the maximum value the force of friction equals the downward push due to gravity , mgsinθ/2 Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Ajit Singh Verma IITD
Dear kaushik ,
(a) AS we increase the angle the force of gravity along the incline i.e mgsinθ increases and the normal component to the plane mgcosθ decreases . SO , the maximum angl is reached when the downward force equals the maximum friction force.
so , mgsinθ = µmgcosθ
so maximum angle is θ = tan-1 (µ) = tan-1 (.3) = 16.7 deg
b) when the angle is lesser than the maximum value the force of friction equals the downward push due to gravity , mgsinθ/2
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
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Ajit Singh Verma IITD
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