Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
a boy throws a ball upwards with an angle of 45 degrees of velocity 100 m/s that makes a parabola in the sky. what will be the Time taken by the ball, total distance and displacement?????
T = 2Usin@/g = 2*100/10sqrt2 =10sqrt2 (total time) displacement = range of projectile = u2sin2@/g=u2sin90/g =1000m
T = 2Usin@/g = 2*100/10sqrt2
=10sqrt2 (total time)
displacement = range of projectile = u2sin2@/g=u2sin90/g
=1000m
the initial velocity of the ball is 100m/s and angle of projection is 45 degrees therefore time taken by the ball to come to the ground is T=u*sin theta/2g the total distance covered by the ball and the displacement of the ball is the same thing the formula for the total distance covered by the ball is=horizontal speed*time taken by the ball horizontal speed of the ball is u*cos theta put the values and get the answer
the initial velocity of the ball is 100m/s and angle of projection is 45 degrees
therefore time taken by the ball to come to the ground is T=u*sin theta/2g
the total distance covered by the ball and the displacement of the ball is the same thing
the formula for the total distance covered by the ball is=horizontal speed*time taken by the ball
horizontal speed of the ball is u*cos theta
put the values and get the answer
The time taken by the ball is 2usin45/g.The displacement is the range of the projectile which comes out to be 1km.
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -