In a square field of side 10m, we move along two adjacent sides starting from one corner and ending at the opposite corner. What is our displacement.

Dear studentm

Displacement in this case= diagonal of the square=10 root 2 m

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Sagar Singh

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let abcd be a square ...

if we from vertex a move along two adjecent sides then finally we reach to vertex c (the opposite vertex) ...

from pythogorus theorem

 (ab)²+(bc)² = (ac)²

ac is the displacement  , ab = ac = 10          (each side is equal )

 ac = root((ab)²+(bc)²)=(100+100)^1/2

                                 =(200)^1/2m

(200)^1/2 m is displacement

Let one side to be x

displacement = the minimum possible distance between 2 points of movement

therefore in a square according to problem, the displacement is the diagonal of that square

displacement is the distance between the initial and the final point. As we started from one vertex and stopped at the opposite vertex, so the displacement is equal to the length of the diagonal. Side of the square is 10m

therefore the length of the diagonal is =10*square root(2)

10*1.414=14.4m