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In a square field of side 10m, we move along two adjacent sides starting from one corner and ending at the opposite corner. What is our displacement.
Dear studentm Displacement in this case= diagonal of the square=10 root 2 m Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
Dear studentm
Displacement in this case= diagonal of the square=10 root 2 m
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi sagarsingh24.iitd@gmail.com
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All the best.
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Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
sagarsingh24.iitd@gmail.com
let abcd be a square ... if we from vertex a move along two adjecent sides then finally we reach to vertex c (the opposite vertex) ... from pythogorus theorem (ab)2+(bc)2 = (ac)2 ac is the displacement , ab = ac = 10 (each side is equal ) ac = root((ab)2+(bc)2)=(100+100)1/2 =(200)1/2m (200)1/2 m is displacement
let abcd be a square ...
if we from vertex a move along two adjecent sides then finally we reach to vertex c (the opposite vertex) ...
from pythogorus theorem
(ab)2+(bc)2 = (ac)2
ac is the displacement , ab = ac = 10 (each side is equal )
ac = root((ab)2+(bc)2)=(100+100)1/2
=(200)1/2m
(200)1/2 m is displacement
Let one side to be x displacement = the minimum possible distance between 2 points of movement therefore in a square according to problem, the displacement is the diagonal of that square
Let one side to be x
displacement = the minimum possible distance between 2 points of movement
therefore in a square according to problem, the displacement is the diagonal of that square
displacement is the distance between the initial and the final point. As we started from one vertex and stopped at the opposite vertex, so the displacement is equal to the length of the diagonal. Side of the square is 10m therefore the length of the diagonal is =10*square root(2) 10*1.414=14.4m
displacement is the distance between the initial and the final point. As we started from one vertex and stopped at the opposite vertex, so the displacement is equal to the length of the diagonal. Side of the square is 10m
therefore the length of the diagonal is =10*square root(2)
10*1.414=14.4m
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