Dear studentm
Displacement in this case= diagonal of the square=10 root 2 m






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let abcd be a square ...
if we from vertex a move along two adjecent sides then finally we reach to vertex c (the opposite vertex) ...
from pythogorus theorem
 (ab)2+(bc)2 = (ac)2
ac is the displacement  , ab = ac = 10          (each side is equal )
 ac = root((ab)2+(bc)2)=(100+100)1/2
                                 =(200)1/2m
(200)1/2 m is displacement
						

							
Let one side to be x
displacement = the minimum possible distance between 2 points of movement
therefore in a square according to problem, the displacement is the diagonal of that square
 

						

							
displacement is the distance between the initial and the final point. As we started from one vertex and stopped at the opposite vertex, so the displacement is equal to the length of the diagonal. Side of the square is 10m
therefore the length of the diagonal is =10*square root(2)
10*1.414=14.4m