#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A body falling from rest covers distances s1 and s2 in first and second seconds respectively. Calculate the ratio s1/s2.Plz help me out. Thanks in advance.

419 Points
10 years ago

Dear Jayati

Refer the pic for the solution

All the best.

AKASH GOYAL

Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

509 Points
10 years ago

body is falling from rest so its initial velocity = u=0

accleration due to gravity = g

distance covered in first second = ut + at2/2                   (u=0)

s1  =gt2/2=g/2     .......1                   (t=1 , a=g)

distance covered from t=0 to t=2 sec is

=ut+at2/2=at2/2                         (u=0)

=2g                              (t=2)

distance covered in second second = s2 =  2g - g/2=3g/2  ..................2

divide 1 & 2

s1/s2 = 1/3 ans