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Grade: 10


A body falling from rest covers distances s1 and s2 in first and second seconds respectively. Calculate the ratio s1/s2. Plz help me out. Thanks in advance.

9 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points

Dear Jayati

Refer the pic for the solution

All the best.                                                           




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9 years ago
vikas askiitian expert
509 Points

body is falling from rest so its initial velocity = u=0

accleration due to gravity = g

distance covered in first second = ut + at2/2                   (u=0)

                                           s1  =gt2/2=g/2     .......1                   (t=1 , a=g)

distance covered from t=0 to t=2 sec is

                               =ut+at2/2=at2/2                         (u=0)

                                             =2g                              (t=2)

distance covered in second second = s2 =  2g - g/2=3g/2  ..................2

divide 1 & 2

 s1/s2 = 1/3 ans

9 years ago
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