A body falling from rest covers distances s1 and s2 in first and second seconds respectively. Calculate the ratio s1/s2.

Plz help me out. Thanks in advance.

Dear Jayati

Refer the pic for the solution

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body is falling from rest so its initial velocity = u=0

accleration due to gravity = g

distance covered in first second = ut + at²/2                   (u=0)

                                           s₁  =gt²/2=g/2     .......1                   (t=1 , a=g)

distance covered from t=0 to t=2 sec is

                               =ut+at²/2=at²/2                         (u=0)

                                             =2g                              (t=2)

distance covered in second second = s₂ =  2g - g/2=3g/2  ..................2

divide 1 & 2

 s₁/s₂ = 1/3 ans