MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 9
        a boy throws a ball upwards with an angle of 45 degrees of velocity 100 m/s that makes a semicircle in the sky. what will be the max. height of the ball????
7 years ago

Answers : (5)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
							

Dear Shivam

initial upward velocity u=100/√2 m/s

at highest point velocity is zero

using v2=u2-2gH

put v=0

H=u2/2g = 10000/(2x2x10)= 250m

 

All the best.                                                           

AKASH GOYAL

AskiitiansExpert-IITD

 

Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

 

7 years ago
vikas askiitian expert
509 Points
							

range of projectile = u2sin2@/g = u2/g             (at @=45)

it forms a semicircle in sky so this range is equal to diameter of this circle...

now , D = u2/g

D =2R                                          (R is radius of semicircle)

R = u2/2g

maximum height will be radius of this semicircle

Hmax = u2/2g=500m

7 years ago
Anirud Thyagharajan
14 Points
							

hello ,

since the formula for height of a projectile is u2sin2angle/2g, the answer can be calculated thus...

7 years ago
bhargav teja
33 Points
							

since it makes a semi circle in skymax height is half of i t's range 

  range R=U2SIN2(ANGLE)/g

     100*100/10

=1000

         then its max.height =500

7 years ago
Fawz Naim
37 Points
							

the ball will undergo a projectile motion. the formula for the max. height attained by the ball is =u^2cos^theta/2g

theta=45 deg

u=100m/s  g=10m/s^2

therefore

H=10000*0.5/2*10

=250m

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 276 off

COUPON CODE: SELF10


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 297 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details