Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A chain of mass M is placed on a smooth table with 1/3 of its length L hanging over the edge. the work done in pulling the chain back to the surface of the table. a) MgL/3 b)MgL/6 c)MgL/9 d)MgL/18
A chain of mass M is placed on a smooth table with 1/3 of its length L hanging over the edge. the work done in pulling the chain back to the surface of the table.
a) MgL/3
b)MgL/6
c)MgL/9
d)MgL/18
The mass of the chain is M and 1/3 of it is habging down i.e. L/3 length of chain is hanging down. The work done in pulling the hanging part of chain up is =M*g*h h=L/3 W=MgL/3 option (a) is correct
The mass of the chain is M and 1/3 of it is habging down i.e. L/3 length of chain is hanging down. The work done in pulling the hanging part of chain up is =M*g*h
h=L/3
W=MgL/3
option (a) is correct
mass of 1/3rd section of chain will be M/3 now consider the center of mass of hanging part will be at center of hanging part... workdone in pulling hanging part above the table is equal to workdone in pulling center of mass of hanging part to the table... displacement of center of mass (h)= l/6 workdone = (dm)gh =Mgl/18
mass of 1/3rd section of chain will be M/3
now consider the center of mass of hanging part will be at center of hanging part...
workdone in pulling hanging part above the table is equal to workdone in pulling center of mass of hanging part to the table...
displacement of center of mass (h)= l/6
workdone = (dm)gh
=Mgl/18
The mass of 1/3 L=m/3The force =mg/3Now work done= force ×displacement= Mg/3×1/3L = mgL/9 So the work done in pulling the chain = MgL/9
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -