A chain of mass M is placed on a smooth table with 1/3 of its length L hanging over the edge. the work done in pulling the chain back to the surface of the table.
a) MgL/3
b)MgL/6
c)MgL/9
d)MgL/18
The mass of the chain is M and 1/3 of it is habging down i.e. L/3 length of chain is hanging down. The work done in pulling the hanging part of chain up is =M*g*h
h=L/3
W=MgL/3
option (a) is correct
Approved Tutor Answer15 Years agomass of 1/3rd section of chain will be M/3
now consider the center of mass of hanging part will be at center of hanging part...
workdone in pulling hanging part above the table is equal to workdone in pulling center of mass of hanging part to the table...
displacement of center of mass (h)= l/6
workdone = (dm)gh
=Mgl/18
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