Mechanics> work,energy and power...

A chain of mass M is placed on a smooth table with 1/3 of its length L hanging over the edge. the work done in pulling the chain back to the surface of the table.

a) MgL/3

b)MgL/6

c)MgL/9

d)MgL/18

Rohit Singh , 14 Years ago

Grade 12

3 Answers

Fawz Naim

Last Activity: 14 Years ago

The mass of the chain is M and 1/3 of it is habging down i.e. L/3 length of chain is hanging down. The work done in pulling the hanging part of chain up is =M*g*h

h=L/3

W=MgL/3

option (a) is correct

vikas askiitian expert

Last Activity: 14 Years ago

mass of 1/3rd section of chain will be M/3

now consider the center of mass of hanging part will be at center of hanging part...

workdone in pulling hanging part above the table is equal to workdone in pulling center of mass of hanging part to the table...

displacement of center of mass (h)= l/6

workdone = (dm)gh

=Mgl/18

Approved

Vaagisha

Last Activity: 7 Years ago

The mass of 1/3 L=m/3

The force =mg/3

Now work done= force ×displacement

= Mg/3×1/3L = mgL/9

So the work done in pulling the chain =

MgL/9

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Mechanics> work,energy and power...

A chain of mass M is placed on a smooth table with 1/3 of its length L hanging over the edge. the work done in pulling the chain back to the surface of the table. a) MgL/3 b)MgL/6 c)MgL/9 d)MgL/18

Rohit Singh , 14 Years ago

Fawz Naim

vikas askiitian expert

Vaagisha

LIVE ONLINE CLASSES

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