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# An aeroplane is flying along the horizonyal at a velocity Vo starts to ascend describing a circle with height ‘h’ above the initial level of motion acc. To the expression v2 =vo 2-2ßh the velocity of plane at the upper point of trajectory is v1=V0/2. Find the acceleration magnitude of the plane when its velocity is directed vertically upwards.

Sandeep Pathak
7 years ago
The velocity of the aeroplane is vertical when it has completed quarter circle. In that case, there are two components of acceleration:
• Centripetal acceleration, acdirected towards center, i.e. horizontal.
• Tangential acceleration, at= g, directed downwards.
Let’s assume the velocity be v1when the aeroplane is moving vertically. Then,

Also, it is given

This gives