Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
a baloon of mass 100kg is at 100mts from the ground . a man of 50kg mass climbs the rope of the baloon with velocity 0.3m/s relative to the baloon. in which direction will the baloon move and with what velocity?
a baloon of mass 100kg is at 100mts from the ground . a man of 50kg mass climbs the rope of the baloon with velocity 0.3m/s relative to the
baloon. in which direction will the baloon move and with what velocity?
take downward as negative & upward as positive ....here weight of man is balanced by baloon so no net force acts in the system of baloon + man... due to motion of man in upward direction the baloon will move in downward direction according to momentam conservation... velocity of man = Vm wrt to baloon let velocity of baloon is Vb then from conservation of momentam in Y direction m(Vm - Vb) - MVb = 0 ( here momentam is wrt to earth) mVm = (M+m)Vb ( mass of man & baloon are m & M respectively) Vb = mVm/(M+m) ....... Vb = 50*0.3/150 = 0.1m/s
take downward as negative & upward as positive ....here weight of man is balanced by baloon so no net force acts in the system of baloon + man...
due to motion of man in upward direction the baloon will move in downward direction according to momentam conservation...
velocity of man = Vm wrt to baloon
let velocity of baloon is Vb then
from conservation of momentam in Y direction
m(Vm - Vb) - MVb = 0 ( here momentam is wrt to earth)
mVm = (M+m)Vb ( mass of man & baloon are m & M respectively)
Vb = mVm/(M+m) .......
Vb = 50*0.3/150 = 0.1m/s
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -