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A particle projected from ground with speed u at an angle q with the horizontal. Radius of curvature of trajectory of the particle








 
A particle projected from ground with speed u at an angle q with the horizontal. Radius of curvature of trajectory of the particle

Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Equation of Trajectory (Path of projectile)

At any instant t
x= ucosØ.t
» t= x/(ucosØ)

Also , y= usinØ.t - (1/2)gt2

Substituting for t
y= usinØ.x/(ucosØ) - (1/2)g[x/(ucosØ)]
2

» y= x.tanØ - [(1/2)g.sec2Ø.x2 ]/u2

This equation is of the form y= ax + bx2 where 'a' and 'b are constants.This is the equation of a parabola.Thus,the path of a projectile is a parabola .

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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Sagar Singh

B.Tech, IIT Delhi

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Please do not post the same doubt again n again...

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

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