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Grade 12Mechanics

A particle projected from ground with speed u at an angle "a" with the horizontal. Radius of curvature of trajectory of the particle

ASHUTOSH SAHU

15 Years agoGrade 12

1 Answer

SAGAR SINGH - IIT DELHI

15 Years ago

Dear student,

Equation of Trajectory (Path of projectile)

At any instant t
x= ucosØ.t
» t= x/(ucosØ)

Also , y= usinØ.t - (1/2)gt²

Substituting for t
y= usinØ.x/(ucosØ) - (1/2)g[x/(ucosØ)]²

» y= x.tanØ - [(1/2)g.sec²Ø.x²]/u²

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