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a small pendulum of mass m is attached to a cuboidal block of same mass m. pendulum is is lifted up at an angle of 37 degree and given a tangential velocity of Vo(lg/5)^-2.the length of string is l.then what should be the minimum coefficient of friction so the block will not slide?

nehal helal , 15 Years ago
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anser 1 Answers
Askiitians Tutor Team

To determine the minimum coefficient of friction required to prevent the block from sliding when the pendulum is lifted and given an initial tangential velocity, we need to analyze the forces acting on the system. Let's break this down step by step.

Understanding the Forces at Play

When the pendulum is lifted to an angle of 37 degrees and given a tangential velocity, several forces come into play:

  • Gravitational Force: This acts downward on both the pendulum and the block.
  • Tension in the String: This force acts along the string and has both vertical and horizontal components.
  • Frictional Force: This opposes the motion of the block and is dependent on the normal force and the coefficient of friction.

Calculating the Forces

First, let's analyze the forces acting on the block. The gravitational force acting on the block is given by:

F_gravity = m * g

Where g is the acceleration due to gravity.

Next, we need to find the components of the tension in the string when the pendulum is at an angle of 37 degrees. The tension can be broken down into two components:

  • T_vertical = T * cos(37°)
  • T_horizontal = T * sin(37°)

At the same time, the block experiences a normal force N equal to the weight of the block minus the vertical component of the tension:

N = m * g - T * cos(37°)

Frictional Force and Motion

The frictional force F_friction that prevents the block from sliding is given by:

F_friction = μ * N

Where μ is the coefficient of friction.

For the block to remain stationary, the frictional force must be greater than or equal to the horizontal component of the tension:

μ * N ≥ T * sin(37°)

Finding the Tension

To find the tension T, we can use the centripetal force required for the pendulum's circular motion. The centripetal force is provided by the horizontal component of the tension:

T * sin(37°) = m * (V^2 / l)

Where V is the tangential velocity given as V₀ = (g / 5)^(1/2).

Substituting Values

Now, substituting the expression for V into the tension equation:

T * sin(37°) = m * ((g / 5) / l)

From this, we can express T:

T = (m * (g / 5) / l) / sin(37°)

Combining Everything

Now, substituting T back into the friction equation:

μ * (m * g - T * cos(37°)) ≥ T * sin(37°)

After substituting for T and simplifying, we can solve for the coefficient of friction μ.

Final Calculation

After performing the calculations, we find that:

μ = (T * sin(37°)) / (m * g - T * cos(37°))

By substituting the values and simplifying, we can find the minimum coefficient of friction required to keep the block from sliding.

In summary, the minimum coefficient of friction depends on the angle of the pendulum, the mass of the block, and the initial velocity given to the pendulum. By carefully analyzing the forces and applying the principles of physics, we can derive the necessary conditions for equilibrium in this system.

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