Car A has an acceleration of 2 m/s^2 due east and car B, 4 m/s^2 due north. What is the acceleration of car B with respect to car A?

Dear Chanchal

a_A=2i

a_B=4j

rel acceleration = a_B - a_A= 4j-2i

magnitude=√42+22=√20 m/s²

direction=tan^-1(4/2)=tan^-12=63.43⁰ from west towards north

All the best.

AKASH GOYAL

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accleration of car A is a = 2i              (due to east)

accleration of car B is b =4j              (due to north)

accleration of B wrt A is a_{rel =} a-b

 a_rel = 2i - 4j

 a = (2²+4²)^1/2 = 2(sqrt5)m/s² in magnitude

accleration of car A is a = 2i (due to east) accleration of car B is b =4j (due to north) accleration of B wrt A is arel = a-b arel = 2i - 4j a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude