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Grade: 11
        

Car A has an acceleration of 2 m/s^2 due east and car B, 4 m/s^2 due north. What is the acceleration of car B with respect to car A?

7 years ago

Answers : (3)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
							

Dear Chanchal

aA=2i

aB=4j

rel acceleration = aB - aA= 4j-2i

magnitude=√42+22=√20 m/s2

direction=tan-1(4/2)=tan-12=63.430 from west towards north

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

 

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7 years ago
vikas askiitian expert
509 Points
							

accleration of car A is a = 2i              (due to east)

accleration of car B is b =4j              (due to north)

accleration of B wrt A is arel = a-b

 arel = 2i - 4j

 a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude

7 years ago
Deepak Sharma
18 Points
							accleration of car A is a = 2i              (due to east)

accleration of car B is b =4j              (due to north)

accleration of B wrt A is arel = a-b

 arel = 2i - 4j

 a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude

 

						
7 years ago
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