# Car A has an acceleration of 2 m/s^2 due east and car B, 4 m/s^2 due north. What is the acceleration of car B with respect to car A?

420 Points
13 years ago

Dear Chanchal

aA=2i

aB=4j

rel acceleration = aB - aA= 4j-2i

magnitude=√42+22=√20 m/s2

direction=tan-1(4/2)=tan-12=63.430 from west towards north

All the best.

AKASH GOYAL

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509 Points
13 years ago

accleration of car A is a = 2i              (due to east)

accleration of car B is b =4j              (due to north)

accleration of B wrt A is arel = a-b

arel = 2i - 4j

a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude

Deepak Sharma
18 Points
13 years ago
accleration of car A is a = 2i (due to east) accleration of car B is b =4j (due to north) accleration of B wrt A is arel = a-b arel = 2i - 4j a = (22+42)1/2 = 2(sqrt5)m/s2 in magnitude