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A bullet of mass 1g shot vertically up by a gun gives a force 2N for 0.001s.Calculate the maximum height attained by a bullet. Neglect air friction and take g=10ms -2 . Solve this problem…………..
force = change in momentam/time 2 =(mv-mu)/10-3 u=0 so v = 2m/s now we have v2 = u2+2as when bullet reaches maximum height then its velocity becomes 0.. 0 = u2-2gH H=u2/2g=0.2m
force = change in momentam/time
2 =(mv-mu)/10-3
u=0 so
v = 2m/s
now we have v2 = u2+2as
when bullet reaches maximum height then its velocity becomes 0..
0 = u2-2gH
H=u2/2g=0.2m
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