is the orbital velocity the minimumlaunching velocity for making the satellite revolve around the earth asdefiniton says ?If it is so the acc. 2 the eqn. , v0=R(g/R+h)^1/2 , ifthe destination orbit is higher, the the orbital velocity, ie theminimum launching velocity must be lower??HOW CAN IT BE SO??OR Is itlike this ;As the satellite advances into more height, the velocityshould decrease,(ie , it should be programmed accprdingly) so as toreach the fixed destination orbit which means that the orbital velocityis a variable??? PLZ EXPL

Dear student,

Orbital Velocity is the velocity which is give to an artificial earth's satellite a few hundred kilometers above the earth's surface so that it may start revolving round the earth. It is denoted by V_o.

Expression for orbital velocity

Let, m = Mass of satellite

r = radius of circular orbit of satellite

h = height of satellite above surface of earth.

R = radius of earth

V_o = orbital velocity

M = Mass of the earth.

The

required by the satellite to keep moving in a circular orbit is produced by the gravitational force

between the satellite and the earth. Therefore,

Here r=R+h

Let gh be the acceleration due to gravity at heigh h

Therefore, weight of satellite = Mgh

Force of attraction between body (Satellite) and earth must be balance by weight of satellite.

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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