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(a)3v cos x

(b)2v cos x

(c)1.5v cos x

(d)1.5^2v cos x

11 years ago

Hi

ans: 3vcosx

At the top of its path, vel is vcos x only in horizontal direction , so after explosion to retrace its path , the velocity of one of the equal masses should be -vcos x . therefore now if v conserve the momentum, then 2mvcosx = -mvcosx + mv' . calculate v' .

11 years ago

hi vaibhav,

dis question is quite straight forward

as velocity at d highest point is v cosx

just apply momentum conservation

m(v cosx) = m/2 (-ucosx ) + m/2 v1, [ as it is divided into parts of equal mass n one part retraces to d cannon itself so its velocity will be vcosx but wid a negative sign]

we hav to find v1

here simply u get v1= 3v cosx

7 years ago

4 years ago

4 years ago

4 years ago

11 months ago

Dear student,

Please find the solution to your solution to your problem below.

At the top of its path, vel is vcos x only in horizontal direction , so after explosion to retrace its path , the velocity of one of the equal masses should be -vcos x . therefore now if we conserve the momentum,

then 2mvcosx = -mvcosx + mv

Therefore, v = 3vcosx

Hope it helps,

Thanks and regards,

Kushagra

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