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net force on the system=120-50=70N
(total mass)(accleration)=70
7a=70
a=10m/s2 ans
a=F/m
a=(120-50)g/(1+4+2)
a=70g/7
a=10g
Dear student,
In such type of questions first of all find the net force on the system.
Here in the question, Net force on the system=120-50=70N (total mass)(accleration)=70 7a=70 a=10m/s2 Hence acceleration of the system = 10 m/s2 Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Here in the question,
Net force on the system=120-50=70N
a=10m/s2
Hence acceleration of the system = 10 m/s2
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
BOTH ANSWER IS CORRECT.
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