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# Three blocks of masses 1kg,4kg,2kg are placed on a frictionless horizontal plane surface.two forces 120N and 50N are acting on the surface.120 N acts on the 1kg mass particle and 50 N acts in the opposite direction on 2kg masses.Find accelaration of the system.

509 Points
11 years ago

net force on the system=120-50=70N

(total mass)(accleration)=70

7a=70

a=10m/s2 ans

Chiranjeevi .P
29 Points
11 years ago

a=F/m

a=(120-50)g/(1+4+2)

a=70g/7

a=10g

SAGAR SINGH - IIT DELHI
879 Points
11 years ago

Dear student,

In such type of questions first of all find the net force on the system.

Here in the question,

Net force on the system=120-50=70N

(total mass)(accleration)=70

7a=70

a=10m/s2

Hence acceleration of the system = 10 m/s2

All the best.

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Sagar Singh

B.Tech, IIT Delhi