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the radius of gyration of a hemi sphere of mass 'm'and radius 'r' about an axis parallel to diameter at a distance '3r/4'is given by [center of mass of hemisphere lies at a height '3r/8' from base]?

68 Points
11 years ago

Dear  bhargav ,

Since the center of mass of a solid hemisphere is 3/8 R above the circular base; so reducing it to a one particle system, and the moment of inertia of that one particle system is M(3/8 R)^2=M(9/64)R^2.

Now moment of inertia of the particle about an axis parallel to the original one but at a distance of 3/4 R can be obtained using the parallel axis theorem

New M.I. = MR^2(45/64)

All the best.

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