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WHEN THREE BLOCKS OF(DIFFERENT MASSES) ARE PLACED ON TOP OF ONE ANOTHER SUCH THAT THERE IS FRICTION(FRICTION COEFFICIENT DIFFERENT)BETWEEN ALL BLOCKS AND ALSO THE GROUND THEN HOW SHOULD I APPROACH THE PROBLEM WHEN THERE IS A FORCE APPLIED ON THE 2ND BLOCK AND I HAVE FIND THE ACCELERATIONS & THE FRICTIONAL FORCES? WHEN I USE FRICTION=kN ; I GET THE WRONG ANSWERS. PLEASE HELP!

WHEN THREE BLOCKS OF(DIFFERENT MASSES) ARE PLACED ON TOP OF ONE ANOTHER SUCH THAT THERE IS FRICTION(FRICTION COEFFICIENT DIFFERENT)BETWEEN ALL BLOCKS AND ALSO THE GROUND THEN HOW SHOULD I APPROACH THE PROBLEM WHEN THERE IS A FORCE APPLIED ON THE 2ND BLOCK AND I HAVE FIND THE ACCELERATIONS & THE FRICTIONAL FORCES?


WHEN I USE FRICTION=kN ;


I GET THE WRONG ANSWERS. PLEASE HELP!

Grade:

1 Answers

Rathod Shankar AskiitiansExpert-IITB
69 Points
10 years ago

1) consider the block which is under force. so apply newtons method for force equation.

 

sa applied force is F on that block.

here u= co efficeint

N= normal force

friction force f= U*N

F-f1-f3=m2*a

F-u1 * m1 *g-u3*m3*g= m2*a 2  ...... u1 is between m2 amd m1....u3 is between m2 and m3

 

apply same equations on 1st and 3rd blocks. the friction force direction is opposite to f1 and f3.

f3=m3*a3 = u3* m3*g

 

f3=m1*a1 = u1* (m3+m2+m1)*g

 

 

thanks

Rathod Shankar

IIT Bombay

 

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