Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

Question

Chetan Mandayam Nayakar · Answer

Dear Raj,

Let the angle be 'theta'. from conservation of horizontal component of linear momentum, we have

m(vcos(theta)+V)=MV, V= mvcos(theta)/(M-m)

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Chetan Mandayam Nayakar – IIT Madras

Archit Uttarwar · Answer

Dear Raj, Let the angle be 'theta'. from conservation of linear momentum in horizontal direction we have m(vcos(theta)+V)=(M+m) V V= mvcos(theta)/(M)

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Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

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Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

2 Answers

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