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# Q. A railway flat car,whose mass together with the artillery gun is M , moves at a speed V . The gun barrel makes an angle ? with the horizontal. A shell of mass 'm' leaves the barrel at a speed v,relative to the barrel.The what is the speed of the flat car in order to stop after the firing?

Chetan Mandayam Nayakar
312 Points
10 years ago

Dear Raj,

Let the angle be 'theta'.  from conservation of horizontal component of linear momentum, we have

m(vcos(theta)+V)=MV, V= mvcos(theta)/(M-m)

All the best.

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Chetan Mandayam Nayakar – IIT Madras

Archit Uttarwar
35 Points
3 years ago

Dear Raj,

Let the angle be 'theta'. from conservation of linear momentum in horizontal direction  we have
m(vcos(theta)+V)=(M+m)  V
V= mvcos(theta)/(M)