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a figure is mentioned(as i don't know how 2 scrap images in the question) like that.
1)draw a base line
2)a body B of mass 'm' on it
3) the upper end of B is attached to spring then with a string(rounded on a massless pulley)
4) the other part of the string is attached with a body A of mass M.
A is released from rest when the string is in its natural length. for the block B to leave contact with the ground at some stage. what should be the minimum mass of block A ??????????????
Dear Rajan,
you should analyze it that for minimum mass the block b will leave surface at maximum extension of spring, for masses greater, b will leave surface before maximum extension and for lesser masses it will not leave ever.
Let mass of block a be M, we know at maximum extension velocity is 0 also extension in spring will be equal to desendent length by block a
so by conservation of energy
kx2 /2 = Mgx
kx = 2Mg
now fbd of a
kx-Mg = Ma
gives a = g
fbd of b with normal force 0 for leaving surface
ma = kx
mg = 2Mg
M = m/2
which is amaging that we can use 5kg to lift 10 kg wieght by putting a spring in between, otherwise we need to have 10 kg wieght.
like my answer.
For just leaving the surface the normal by surfce will be 0 on block b
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