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Let us assume that the ball was hit with velocity V making an angle 'b' with the horizontal.
So it horizontal component of velocity will be constant and will be equal to v cos b.
Now we know the ball took one sec to move pas the wall and then three more seconds to move the distance when it was above the wall. So it must have taken one more second till it was caught; making the total time interval to 5 seconds.
Also we know the ball travelled 50m in three seconds with a constant horizontal velocity; there fore the horizontal component must be equal to 50/3 m/sec.
Therefor total horizontal distance will be equal to 50/3*5= 250/3 m.
Now if horizontal component is 50/3=v cos b then v sin b= say x.. this will give you the height of the wall as this velocity took one sec to cover the height of the wall.
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