#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Is there something special when an object moves according to the law v=a*sqrt(s) ?

v -velocity
a-constant
s-displacement

actually, the acceleration for this type of motion comes out to be constant.
dv/dt=dv/ds*ds/dt
= [a/2*sqrt(s)]*a.sqrt(s)=a^2/2
can you intuitively explain why this happens ?

509 Points
10 years ago

v=ds/dt=Ksqrt(s)          (k=a^2/2)

ds/sqrt(s)=kdt

2sqrts=kt+c

s=(kt+c)^2 /2

it means graph between time and displacement is parabola......

10 years ago

Hiii shubham

v = a root(x)

dx/dt = a.root(x)

dx/a.root(x) = a.dt

Integrate it ...

2root(x) = a .t

or   x = a^2.t^2/4

x = kt^2

This is a parabolic path with respect to time..

d^2x/dt^2 = 2k  ( constant )

So this is just a projectile motion with object starting from rest...moved with constant acceleration 2k

Regards

Yagya