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NEERAJ PATHAK IIT-BHU Grade: Upto college level

a batsman hits a ball at an angle of 53deg with horizontal at a height of 1m above the ground towards the audience with a velocity of 35m/s. If the distance of first bench from him is 110m and each bench has same height and width then find which bench will be struck by the ball

7 years ago

Answers : (1)

Askiitians_Expert Yagyadutt
askIITians Faculty
74 Points

Hello  Neeraj


Now the ball is struck by the bat at a height of 10 m...and the angle is 53deg it becomes a case like ...a projectile is thrown from a tower ....



Now Velocity is 35 m/s is at an angle of 53 with the it will have two components in horizontal and one in vertical..


Horizontal component = 35.cos(53)  =  21 m/s

Vertical component =  35.sin(53) = 28 m/s


Now vertical velocity = 28 m/s is responsible to bring the ball back to the ground .

and horizontal component will let it to move forwar to the bench ...


So ...Let us calculate what time is taken by the ball to hit the ground...which is due to v=28m/s


 h = ut + 1/2 a t ^2


-1  = 21(t) - 5(t)^2


5t^2 -21 t - 1 = 0  


t =  [21 + root( 461)]/10 


t= 4.2 sec .


Now in this much time the ball will hit the ground...horizontal velocity v = 28 m/s is responsible for the horizontlal move of the let us calculate how far the ball will go and strike...


t = 4.2 sec ...v = 28 m/s


so  distance in horizontal direction (range) = 4.2 X 28  = 117.6 m


The First bench is at 110 ..


So ball strike something ...7.6 m behind the first bench


Given spacing and height of the bench is same ..i.e = 1 m

Then will hit to the eighth bench.....because spacing is 1 m..and extran error is 0.6 it is just 60 cm < 1m

Hence after 7 m...0.6 proves that eight bench is the answer


--------------------------------110 ---------------( 1 bench)(  ) ( ) (  ) (  )  (  )   (  ) (   )


7 years ago
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