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A flowerpot falls from a windowsill 25.0 m above the sidewalk. (a) how fast is the flowerpot moving when it strikes the ground? (b) how much time does a passerby on the sidewalk below have to move out of the way before the flowerpot hits the ground?

A flowerpot falls from a windowsill 25.0 m above the sidewalk.      


(a) how fast is the flowerpot moving when it strikes the ground?


(b) how much time does a passerby on the sidewalk below have to move out of the
        way before the flowerpot hits the ground?

Grade:12

1 Answers

vikas askiitian expert
509 Points
11 years ago

t is the time taken by flower pot to reach the bottom

     t= sqrt2s/g=sqrt5

 now using   v=u +at

                  v=10sqrt5 m/s (velocity with which flower pot hits the ground)

 

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