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A bicycle travels 3.2 km due east in 0.1 h, the 3.2 km at 15.0 degrees east of north in 0.21 h, and finally another 3.2km due east in 0.1 h to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
Dear sachin,
By definition the average velocity is equal to the ratio of the magnitude of the net displacement and the traveled time. The net displacement is shown in the figure.
We can find the x and y components of the vector of net displacement.
The x-component is
The y-component is
Then the magnitude of the net displacement is
The traveled time is 0.1 h + 0.21 h + 0.1 h = 0.41 h. Then the average velocity is
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