Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Nitin Gupta Grade: 11

A bullet of mass 7g is fired into a block of metal of weight 7kg.The block is free to move.Calculate the velocity of bullet if the velocity of block with bullet is 0.7m/s.

Is the answer 350.35m/s?If not then provide the correct one


7 years ago

Answers : (4)

suryakanth AskiitiansExpert-IITB
105 Points

Dear nitin,

By considering the conservation of momentum

m1*V1 = (m1+m2)*v

finding V1,after substuting the values

m1= 7g


v=0.7 m/s

we get V1=700.7 m/s

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


Askiitians Expert

Suryakanth –IITB

7 years ago
vikas askiitian expert
510 Points

applying conservation of momentam

     let intial velocity of bullet is Vb

 intial momentam=MbVb               Mb is the mass of bullet

 finally the whole system moves with velocity.7m/s

  final momentam=(M+Mb).7


intitial momentam = final momettam

so  Vb =4.9049/.007


7 years ago
Karthik Eyan
45 Points

Mass of bullet = 7/1000 kg = 0.007 kg

Mass of block = 7 kg

Momentum is conserved in this case. So:

m1*u1 + m2*u2 = m1*v1 + m2*v2

m - mass [1 - bullet 2- block]

u - Initial velocity

v - final velocity

0.007*u1 = 4.9

u1 = 49/0.007

u1 = 7000 metre per sec.

7 years ago
Stephen Curry
13 Points
										Mass of bullet(m1) = 7 g = 0.007 kgMass of block(m2) = 7 kgSince the block is free to move and it is stationary, initial velocity (u2) = 0Final velocity of the bullet and block = 0.7 m/sInitial velocity of the bullet(u1)  = ?According to the law of conservation of momentum,m1u1 + m2u2 =(m1 + m2)v(Since the bullet and the block are combining to form a single mass)Putting the values of m1, m2, u1, u2 and v, we get0.007u1 + 7 × 0 =(0.007 + 7) × 0.7u1 = 7.007 × 0.7/0.007u1 = 700.7 m/sTherefore, the velocity of the bullet is 700.7 m/s.
5 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details