10g bullet is fired from a 5 kg gun with a velocity of 400 m/s.What is the speed of the recoil.

Is the answer -- 0.8m/s

If not then provide the correct solution

Dear nitin,

Your answer is correct

V_g = - (m_b/mg)* V_b

    = - ((10* 10^^(-3))/5) * 400

    = - (4/5)

    = - 0.8 m/s

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Suryakanth –IITB

Approved

the answer 0.8m/s is correct.

Approved

it is correct, 

according to law of conservation of momentum,

m₁v₁=m₂v₂

v₂ = m1v1/m2

v₂ = (10x10^-3)(400)/5

v₂ = (0.01x400)/5

v₂ = 4/5 = 0.8 ms^-1

Approved

your ans is corect

 from conservation of momentam

  M1.V1 + mv2 =0

              V1=-mv2/M

                  =-4/5=-0.8m/s

Approved