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sunny shah Grade: 12

 A body excutes SHM whose period is 16s.Two second after it passes the equilibrium position,its velocity is 1m/s.The amplitude of SHM is.

7 years ago

Answers : (2)

Anil Pannikar AskiitiansExpert-IITB
85 Points

Dear Sunny,


 as y = Asinwt

so, dy/dt = v = Awcoswt

here w = 2Π/T = Π/8 , v =1and t = 2

plug in all values


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Askiitians Expert

Anil Pannikar

IIT Bombay



7 years ago
vikas askiitian expert
510 Points


 thus v=dx/dt =Awcoswt                                                      (A is amplitude)

 w is angular frequency =2pie/T =pie/8                                   (here T is time period)


 after 2 seconds its velocity is 1

                         1 =Awcoswt =awcospie/4

                         A=toot2/w=8root2/pie is required ans


7 years ago
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