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A body excutes SHM whose period is 16s.Two second after it passes the equilibrium position,its velocity is 1m/s.The amplitude of SHM is.

85 Points
11 years ago

Dear Sunny,

as y = Asinwt

so, dy/dt = v = Awcoswt

here w = 2Π/T = Π/8 , v =1and t = 2

plug in all values

All the best.

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Anil Pannikar

IIT Bombay

509 Points
11 years ago

x=Asinwt

thus v=dx/dt =Awcoswt                                                      (A is amplitude)

w is angular frequency =2pie/T =pie/8                                   (here T is time period)

w=pie/8

after 2 seconds its velocity is 1

1 =Awcoswt =awcospie/4

A=toot2/w=8root2/pie is required ans