A bomb at rest explodes into three fragments of equal masses.Two fragments fly off at right angles to each other with velocity 9m/s and 12m/s.Calculate the speed of the third fragment.Please answer this question.I tried to find out by two ways.By using concept of vectors answer came was 15m/s but by using momentum I got 21m/s.Which one is correct?Or both are wrong?Please provide a full solution and if any of my answer is correct then don't give full solution.

Dear Nitin,

Correct answer is 15 in both cases. use conservation of momentum in x and y direction separatly and find the angle

the 3rd partical makes with axis. Then u can easily substitue in any of the 2 eq. to find out the answer.

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