The potential energy of a 0.2 kg particle moving along the x axis is given by:

U(x) = 8x² - 2x⁴

where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

Question

The potential energy of a 0.2 kg particle moving along the x axis is given by: U(x) = 8x 2 - 2x 4 where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

vikas askiitian expert · Answer

F = -du/dx ={8x^3 - 16x} F=ma a=40(x^3 - 2x) at x=10 a=3.92*10^4

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The potential energy of a 0.2 kg particle moving along the x axis is given by: U(x) = 8x 2 - 2x 4 where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

The potential energy of a 0.2 kg particle moving along the x axis is given by:

U(x) = 8x² - 2x⁴

where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

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The potential energy of a 0.2 kg particle moving along the x axis is given by: U(x) = 8x 2 - 2x 4 where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

The potential energy of a 0.2 kg particle moving along the x axis is given by: U(x) = 8x2 - 2x4 where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

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The potential energy of a 0.2 kg particle moving along the x axis is given by:

U(x) = 8x² - 2x⁴

where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?