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The potential energy of a 0.2 kg particle moving along the x axis is given by: U(x) = 8x 2 - 2x 4 where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

The potential energy of a 0.2 kg particle moving along the x axis is given by:


U(x) = 8x2 - 2x4


where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?

Grade:12

1 Answers

vikas askiitian expert
509 Points
10 years ago

F = -du/dx 

   ={8x^3 - 16x}

 F=ma

 a=40(x^3 - 2x)

at x=10

 a=3.92*10^4

 

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