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The potential energy of a 0.2 kg particle moving along the x axis is given by:
U(x) = 8x2 - 2x4
where U is in Joules and x in meters. When the particle is at x = 10 m, what will be its acceleration?
F = -du/dx
={8x^3 - 16x}
F=ma
a=40(x^3 - 2x)
at x=10
a=3.92*10^4
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