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A 0.2 kg rubber ball is dropped from the window of a building. It strikes the sidewalk below at 30 m/s and rebounds at 20 m/s. Find the change in momentum of the ball as a result of the collision with the side walk (in kg m/s).

ankit sharma , 15 Years ago
Grade 12
anser 2 Answers
OCEAN GODRE

answer will be 2 kgm/s

ApprovedApproved
Last Activity: 15 Years ago
vikas askiitian expert

change in momentum =mdv

                                =m(Vf - Vi)

                                =.2(30-(-20))=10N.S

Last Activity: 15 Years ago
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